Year 12s: what will be the first way you research your future options? >>

Problems Finding Torque

, I'm having problems working out

.

For part 1). I get

{​T} = -\sin \alpha(i) +\cos \alpha(j)

is this correct?

(Where T is the tension force)

For part 2). I am stuck :colondollar:

.

What I did was get

{W} = -mgj

Then get the position vector as

\frac{1}{2}2L\sin \alpha(i) \sin \alpha(j)

Simplifies to

L\sin \alpha(i) \sin \alpha(j)

So the answer is

-mgL\sin \alpha(k)

Is this correct or am I completely off? Also will the end answer contain

\alpha

\theta

?

Thanks

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Reply 2

marcus888

Hi, could someone help me on this please, as a week later I have kept trying to solve it but seem to keep getting confused. Have I worded it wrong, as I can redo it to make it sound clearer if I need to? :s-smilie: