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C2 Integration

Question

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I can't seem to get the right area.
Reply 1
Reply 2
Original post by zed963
Question

Capture.PNG

I can't seem to get the right area.

Can you post your working and the answer you're meant to get?
Reply 3
Reply 4
Original post by notnek
Can you post your working and the answer you're meant to get?


The answer should be 343/6
Reply 5
[5x2x338x]29=(40524372)(208316)=8823[5x^2 - \frac{x^3}{3} - 8x]^9_2 = (405-243-72) - (20-\frac{8}{3}-16) = 88\frac{2}{3}

trapezium = 311231\frac{1}{2}

Area = 3436\dfrac{343}{6}



I am still looking for your error
(edited 10 years ago)
Reply 6


You have 18*3 where you need 18*9
Reply 7
Original post by TenOfThem
You have 18*3 where you need 18*9


Well spotted.

Thanks.
:smile:
Reply 8
Original post by TenOfThem
[5x2x338x]29=(40524372)(208316)=8823[5x^2 - \frac{x^3}{3} - 8x]^9_2 = (405-243-72) - (20-\frac{8}{3}-16) = 88\frac{2}{3}

trapezium = 311231\frac{1}{2}

Area = 3436\dfrac{343}{6}



I am still looking for your error


Did you just work out the total area under the curve subtract the area of the trapezium?
Reply 9
Original post by zed963
Did you just work out the total area under the curve subtract the area of the trapezium?


Of course :smile:

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