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e^(x) and ln asymptotes

How do i find the asymptotes for these fuctions?

For example: 144-36e^(-2x)

How do i find the horizontal asymptote for this?

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Original post by QuantumSuicide
How do i find the asymptotes for these fuctions?

For example: 144-36e^(-2x)

How do i find the horizontal asymptote for this?

Posted from TSR Mobile


Investigate to see what happens to trhe value of the function as x tends to infinity.
In the example you have quoted, e2x e^{-2x} will get smaller and smaller as x gets larger and so will tend to zero. hence the asymptote in this case would be y=144.
Original post by QuantumSuicide
How do i find the asymptotes for these fuctions?

For example: 144-36e^(-2x)

How do i find the horizontal asymptote for this?

Posted from TSR Mobile


Test increasingly large negative and positive values of x

As x becomes negative and large, e^(-2x) becomes increasingly large, so f(x) becomes increasingly negative - no asymptote.

As x becomes positive and large, e^(-2x) becomes increasingly small, so f(x) approaches 144 - hence y=144 is an asymptote

EDIT: See above, beaten to it!
(edited 10 years ago)
Reply 3
Original post by brianeverit
Investigate to see what happens to trhe value of the function as x tends to infinity.
In the example you have quoted, e2x e^{-2x} will get smaller and smaller as x gets larger and so will tend to zero. hence the asymptote in this case would be y=144.


I see. Is the method the same for finding vertical asymptotes and the function lnx?

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Reply 4
Original post by QuantumSuicide
How do i find the asymptotes for these fuctions?

For example: 144-36e^(-2x)

How do i find the horizontal asymptote for this?

Posted from TSR Mobile



Also if you know that the asymptote of ex e^{-x} is y = 0, you could use transformations of graphs to shift the curve 144 units upwards so the new asymptote will be at y = 144
Reply 5
Thank you, maths homies

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