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C1 Diff

I can't seem to understand part c of this question

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Reply 1

I did this paper and did what you did with the triangle. Which was right so I guess we have the right method :rolleyes:
Reply 3
Original post by Super199
I did this paper and did what you did with the triangle. Which was right so I guess we have the right method :rolleyes:


So did you split the triangle in half and then calculate the area?

I get it to be 12 but the markscheme says otherwise.
Original post by zed963
So did you split the triangle in half and then calculate the area?

I get it to be 12 but the markscheme says otherwise.

Nope I just did 121523\frac{1}{2}*\frac{15}{2}*3 Which was right but I mean there isn't a right angle triangle which is a bit confusing. I thought you could only do that with a right angled triangle.
(edited 9 years ago)
Reply 5
Original post by Super199
Nope I just did 121523\frac{1}{2}*\frac{15}{2}*3 Which was right but I mean there isn't a right angle triangle which is a bit confusing. I thought you could only do that with a right angled triangle.


Yeah exactly, but :s-smilie:
Original post by zed963
So did you split the triangle in half and then calculate the area?

I get it to be 12 but the markscheme says otherwise.


I got 45/4 mate
Reply 7
Original post by Galileo Galilei
I got 45/4 mate


Yeah that's what the markscheme says but I don't have a right angled triangle so how'd I calculate the area?
Original post by zed963
Yeah exactly, but :s-smilie:


What is the answer?
Original post by zed963
Yeah that's what the markscheme says but I don't have a right angled triangle so how'd I calculate the area?


It is a right angled triangle bro! The calculation I used was 1/2 * 15/2 * 3
Reply 10
Original post by Galileo Galilei
It is a right angled triangle bro! The calculation I used was 1/2 * 15/2 * 3


Check the image on post 3, let me know what I've done wrong please.
Original post by Galileo Galilei
It is a right angled triangle bro! The calculation I used was 1/2 * 15/2 * 3

Post your diagram please :smile:
Original post by Super199
Post your diagram please :smile:


5 mins!
Original post by Super199
Nope I just did 121523\frac{1}{2}*\frac{15}{2}*3 Which was right but I mean there isn't a right angle triangle which is a bit confusing. I thought you could only do that with a right angled triangle.


1/2base*height works for every triangle.For non right angled trigonometry the height isn't one of the side lengths, which can make it difficult to work out the height so you generally use 1/2absinc but the height and base of that triangle are easy to calculate in the 1/2absinc bsinc is the height.
Reply 14
Original post by Super199
Post your diagram please :smile:


Did you get the same diagram as me?
Reply 15
Original post by zed963
Check the image on post 3, let me know what I've done wrong please.


Is it not just 7.5 x 2 divided by 2?

edit: d'oh I meant x 3 divided by 2
(edited 9 years ago)
Original post by zed963
Did you get the same diagram as me?

Yh I did
Reply 17
Original post by Pride
Is it not just 7.5 x 2 divided by 2?


The triangle I've got isn't a right angled triangle. So I can't apply that formula. It's times by 3.
Original post by Dalek1099
1/2base*height works for every triangle.For non right angled trigonometry the height isn't one of the side lengths, which can make it difficult to work out the height so you generally use 1/2absinc but the height and base of that triangle are easy to calculate in the 1/2absinc bsinc is the height.


You should note that the 0.5*base*height is a special case of 0.5*a*b*sin(c) where the angle c is 90 degrees. :smile:
Reply 19
Original post by Super199
Post your diagram please :smile:


So you're doing C1,C2 and S1? I'm assuming.

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