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differentiation question

Find the coordinates of the points on these curves where the gradient is zero.
Done the differentiation bit just stuck on getting a value from x from dy/dx equation. Question 1H by the way. Thanks
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BabyMaths
Original post by sunnytunny92
Find the coordinates of the points on these curves where the gradient is zero.
Done the differentiation bit just stuck on getting a value from x from dy/dx equation. Question 1H by the way. Thanks


I'll assume that you got dydx=12x−1/2−12x−3/2\frac{dy}{dx}=\frac{1}{2}x^{-1/2}-\frac{1}{2}x^{-3/2}

Set it equal to zero and try a few steps. Show us what you get.
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sunnytunny92
OP
could you deduce then that 2√x - 2(√x)^3 = 0
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sunnytunny92
OP
Original post by BabyMaths
I'll assume that you got dydx=12x−1/2−12x−3/2\frac{dy}{dx}=\frac{1}{2}x^{-1/2}-\frac{1}{2}x^{-3/2}

Set it equal to zero and try a few steps. Show us what you get.


ok i dont know how to go about the question from here
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TenOfThem
18
Original post by sunnytunny92
ok i dont know how to go about the question from here


Given you have fractions - you need to multiply through by something

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