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Integration help please :)

Hi guys,
I cant get any further than this at the moment and if anyone could help it would be greatly appreciated :smile: thanks

ImageUploadedByStudent Room1398187236.848514.jpg

The question is in the top left hand corner btw


Posted from TSR Mobile
Reply 1
Original post by Physics4Life
Hi guys,
I cant get any further than this at the moment and if anyone could help it would be greatly appreciated :smile: thanks

ImageUploadedByStudent Room1398187236.848514.jpg

The question is in the top left hand corner btw


Posted from TSR Mobile



1x+x1/3=x1/3x2/3+1\displaystyle \frac{1}{x+x^{1/3}}=\frac{x^{-1/3}}{x^{2/3}+1}
Reply 2
Original post by Physics4Life
Hi guys,
I cant get any further than this at the moment and if anyone could help it would be greatly appreciated :smile: thanks

ImageUploadedByStudent Room1398187236.848514.jpg

The question is in the top left hand corner btw


Posted from TSR Mobile


f(x)f(x)dx=lnf(x)\displaystyle \int \dfrac{f'(x)}{f(x)} dx = \ln |f(x)|
Reply 3
Original post by BabyMaths
1x+x1/3=x1/3x2/3+1\displaystyle \frac{1}{x+x^{1/3}}=\frac{x^{-1/3}}{x^{2/3}+1}


I'm not quite sure how you got this...?

Original post by TenOfThem
f(x)f(x)dx=lnf(x)\displaystyle \int \dfrac{f'(x)}{f(x)} dx = \ln |f(x)|


Oh yeah I can't believe i forgot that :s: rookie error

So i got an answer of 3/2ln|u^2 + 1| + c for my integration and so then i just change it back to x's i think :P thanks for the help :smile:
(edited 10 years ago)
Reply 4
Original post by Physics4Life
I'm not quite sure how you got this...?



Multiply top and bottom by x1/3x^{-1/3}.
Reply 5
Original post by BabyMaths
Multiply top and bottom by x1/3x^{-1/3}.


Oh okay, I see now :P
Reply 6
Original post by Physics4Life

Oh yeah I can't believe i forgot that :s: rookie error

So i got an answer of 3/2ln|u^2 + 1| + c for my integration and so then i just change it back to x's i think :P thanks for the help :smile:


yep, no problem :smile:

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