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Surface integral question

Hi, can someone help me with this question?
Reply 1
Original post by number23
Hi, can someone help me with this question?


Anyone?
Reply 2
I did this a while back so this might be wrong but it might ring a bell...

The route I'm thinking of is splitting the integral into 2 parts, where dA=dxdy (or the other way around, whichever's easiest) and then integrating twice with respect to each variable with its limits.
Reply 3
Let γ:I×JR3\gamma: I\times J \to \mathbb{R}^3 parametise SS, where II and JJ are real intervals. Then
SF.dA:=IJF(γ(x,y))(γx×γy)dydx\displaystyle\int_S F . dA := \int_I \int_J F(\gamma(x,y)) \cdot \left(\frac{\partial \gamma}{\partial x} \times \frac{\partial \gamma}{\partial y} \right) dy dx.

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