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Solving natural logs equation

2ln(x6)=lnx2\ln (x-6) = \ln x

How do I go about solving this? :eek:
Original post by Substitution
2ln(x6)=lnx2\ln (x-6) = \ln x

How do I go about solving this? :eek:


Note that alnx=lnxaa \ln x = \ln x^a
Reply 2
Original post by Mr M
Note that alnx=lnxaa \ln x = \ln x^a


Yes I got that bit and then am I okay to just ignore the ln and solve the quadratic?
Original post by Substitution
Yes I got that bit and then am I okay to just ignore the ln and solve the quadratic?


Yes. You don't exactly ignore the logarithm but you raise each side to base e (this is exponentiation). Always check your solutions satisfy the original equation.

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