Resistor values in an op amp circuit
The question is attached. It also say that it saturates at +-13v. Don't know how to start on this question.
Original post by Fysiika07
(b) use potential divider rule V = [68/(68+22)]*5
(c) as thermistor gets hot, its resistance decreases, thus V at A increases until it get higher than 4V, which is V at B, output become -ve, diode at output will not allow it to pass through, therefore output will be 0 V
(c) as thermistor gets hot, its resistance decreases, thus V at A increases until it get higher than 4V, which is V at B, output become -ve, diode at output will not allow it to pass through, therefore output will be 0 V
Ah yes thanks, I managed to work out part D too I'd anyone was wondering. If you look closely you can see it's set up as a voltage divider and just apply the rules.
Quick Reply
Related discussions
- HNC science
- HNC electrical principles
- Impedance
- Capacitor Question (PHYS)
- Isaac physics C4a.2 - struggling
- Cell in circuit is reversed
- Help! Electricity igcse physics qs make no sense
- Quick multiple choice question
- A level physics electricity question(1)
- resistance in a parallel circuit
- need help please!
- Why does potential difference increase when resistance increases?
- Isaac Physics.
- AS level Physics Resistances Electricity Question Help
- How does the variable resistor circuit provide a larger current?
- HNC Electrical engineering
- A level physics Electricity question (2)
- OCR A Physics 2018 paper 2 capacitors
- In what circumstance would a variable resistor be unaccepted to vary voltage?
- how to solve this resistor network problem?
