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C2 - Integration

Stuck on part d. I am not sure how to work out R, I mean I could do the area under from 0 to N but not sure what to take away to leave R. Some help would be grateful. :smile:
Original post by Super199
Stuck on part d. I am not sure how to work out R, I mean I could do the area under from 0 to N but not sure what to take away to leave R. Some help would be grateful. :smile:


Split the area into - below the curve O to A and the triangle A to N
Reply 2
Original post by TenOfThem
Split the area into - below the curve O to A and the triangle A to N

Ah I never thought of that, got it now! One more question if you don't mind. :colondollar:
Part c?
Not sure what to do. I'm not sure which things to multiply together. :redface:
If you are unsure which things to multiply together, it is often useful to consider the units.

You have a cross sectional area in m2\text {m}^2 and a rate of flow in m s1\text {m\ s}^{-1}
How can you combine them to get a rate of flow in m3 s1\text {m}^3\ \text {s}^{-1} ?

Then what do you multiply it by to get rate of flow in
Unparseable latex formula:

\text {m}^3\ \text {min}^{-1}}

?

Good luck. :smile:
(edited 9 years ago)
Reply 4
Original post by lazy_fish
If you are unsure which things to multiply together, it is often useful to consider the units.

You have a cross sectional area in m2\text {m}^2 and a rate of flow in m s1\text {m\ s}^{-1}
How can you combine them to get a rate of flow in m3 s1\text {m}^3\ \text {s}^{-1} ?

Then what do you multiply it by to get rate of flow in
Unparseable latex formula:

\text {m}^3\ \text {min}^{-1}}

?

Good luck. :smile:

ah I think I understand. Would it be my cross sectional area*2*60?
Yes. :smile:

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