y= to f(x)
I'm trying to get my head around C1 & C2 transformations and for that I need to understand f(x) notation. I know that f(x) is just another way of writing y= but I don't understand how to get from f(x)=x² to f(x)=x²-6x+11 (as per a past paper question) to find the translation.
Q4b iii from AQA Core 1 Jan 2013, if you're wondering. Full text is: Describe the geometrical transformation that maps the curve with equation y=x²-6x+11 onto the curve with equation y=x².
Q4b iii from AQA Core 1 Jan 2013, if you're wondering. Full text is: Describe the geometrical transformation that maps the curve with equation y=x²-6x+11 onto the curve with equation y=x².
Try completing the square on x^2-6x+11 so it's in the form (x-h)^2+k.
Original post by ktalexander
Try completing the square on x^2-6x+11 so it's in the form (x-h)^2+k.
Absolute lifesaver, thank you so much. Never knew it was that easy!
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