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Physics question GSCE P2

Im really stuck with this question can someone help me and I don't understand the answer which is 9.6 kg m/s
: When the ball reaches the batsman it is travelling at 30m/s . The batsman strikes the ball which moves off at 30m/s in the opposite direction. The ball has a mass of 0.16 kg. Calculate the change in momentum of the ball?
Reply 1
Original post by AlphaNick
For questions like this, it is good to refer to the 'opposite direction' as a negative. So if you've got 30 m/s in one direction, the opposite would be -30 m/s

0.16 * 30 = 4.8 kg m/s
0.16 * -30 = -4.8 kg m/s

So 4.8 - -4.8 = 9.6 kg m/s


Thank you ! :smile:
Momentum = mass × velocity

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