The Student Room Group
its the latter. You choose the one which has the lowest locant (number)
Reply 2
do you not give the double bond the lowest number possible, and therefore 4,4-dimethylpent-2-ene?
hmm good point well i cant remember atm lol havent done chem since june erm....you might be right would make more sense
Reply 4
iceman_jondoe
hmm good point well i cant remember atm lol havent done chem since june erm....you might be right would make more sense


no i think you are actually right! I remember having to add all the numbers and see the lowest sum!
Reply 5
iceman_jondoe
hmm good point well i cant remember atm lol havent done chem since june erm....you might be right would make more sense


i'm not 100% certain.....i might go and dig out my notes and check, just in case

EDIT: From my notes;

[quote]Naming Alkenes

1. The rules for naming alkanes mostly apply, except the ending is now -ene, to show the presence of the carbon to carbon double bond.

2. The location of the double bond must be identified by the number of carbon it starts on (As with the branches, the smallest number is used)[/quote

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