Charge on particle
Hi guys! When i attenpted this oast paper, I got everything except the charge correct... And i still dont underdtand why the charge on the particle is negative.
Can someone help please?
I had used Flemings Left Hand Rule.
I pointed my first finger out of the paper, and my thumb towards the centre if the curvature, so I knew that the particle travelled from p to Q. But what about the charge?
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Can someone help please?
I had used Flemings Left Hand Rule.
I pointed my first finger out of the paper, and my thumb towards the centre if the curvature, so I knew that the particle travelled from p to Q. But what about the charge?
Posted from TSR Mobile
Is it because current would travel from Q to P and since we know by looking at the diagram that the radius is smaller at Q, that this charges particle is travelling from P to Q, i.e. In the opposite direction to the current. Therefore, it must have a negative charge?
Posted from TSR Mobile
Posted from TSR Mobile
Yes.
The direction from P to Q is determined by the fact that
a. the particle must slow down after going through the lead
b. the radius of curvature will be smaller if the speed is smaller
The speed is smaller on the right, so the particle is moving to the right.
Using the LH Rule the conventional + current is right to left.
This means if charges are moving left to right they must be negative.
The direction from P to Q is determined by the fact that
a. the particle must slow down after going through the lead
b. the radius of curvature will be smaller if the speed is smaller
The speed is smaller on the right, so the particle is moving to the right.
Using the LH Rule the conventional + current is right to left.
This means if charges are moving left to right they must be negative.
Original post by Stonebridge
Yes.
The direction from P to Q is determined by the fact that
a. the particle must slow down after going through the lead
b. the radius of curvature will be smaller if the speed is smaller
The speed is smaller on the right, so the particle is moving to the right.
Using the LH Rule the conventional + current is right to left.
This means if charges are moving left to right they must be negative.
The direction from P to Q is determined by the fact that
a. the particle must slow down after going through the lead
b. the radius of curvature will be smaller if the speed is smaller
The speed is smaller on the right, so the particle is moving to the right.
Using the LH Rule the conventional + current is right to left.
This means if charges are moving left to right they must be negative.
Thank you Stonebridge
Posted from TSR Mobile
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