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Mr M's OCR FSMQ Additional Maths June 2014 Answers

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Original post by ab9826
Hi, how many marks would I lose for not putting my answers in question 14 to 3 signofocant figures??


How many s.f. did you use?
Original post by samanton5
14iii) 1 - ((PX=0 + PX=1) x PX=1)


This isn't right.
Reply 42
Avatar for πππ
πππ
1
Original post by Mr M
This isn't right.


It is p(x=0) +[ p(0) x p(1)]
Original post by πππ
It is p(x=0) +[ p(0) x p(1)]


Yes.
Original post by Mr M
1. 1 or 2 marks

2. 2 marks

3. Yes

4. It might be


Dear Sir, Thanks
For question 11(ii) I differentiated but didn't get the right factorisation so how many marks could I get?
Reply 45
Avatar for πππ
πππ
1
For the circle equation I thought ab were the radius!! So I put (x-4)^2 + (y-9)^2 = 20. How many marks out of 3 will I get?
I feel that the question 7 is incorrect? it turns out to be root((-2^2)+(-4^2))= root20, which is clearly 5root2.
Reply 47
Avatar for πππ
πππ
1
I've added up all the marks you have and it comes to 92. Therefore question 10 i and ii come to 8 marks.
Original post by jeevanr21
Dear Sir, Thanks
For question 11(ii) I differentiated but didn't get the right factorisation so how many marks could I get?


Depends how far you got. Possibly 3?
Original post by πππ
For the circle equation I thought ab were the radius!! So I put (x-4)^2 + (y-9)^2 = 20. How many marks out of 3 will I get?


Drop 1 mark.
Original post by TheEpiphany
I feel that the question 7 is incorrect? it turns out to be root((-2^2)+(-4^2))= root20, which is clearly 5root2.


20=4×5=4×5=25\sqrt{20}=\sqrt{4 \times 5}=\sqrt{4} \times \sqrt{5} = 2 \sqrt{5}
Original post by Mr M
20=4×5=4×5=25\sqrt{20}=\sqrt{4 \times 5}=\sqrt{4} \times \sqrt{5} = 2 \sqrt{5}


Ah, I see my mistake. But either way when you square it for the next part of the question, doesn't the r square bit equal 20?
No, 252\sqrt{5} was the diameter, so 5\sqrt{5} was the radius.
Original post by Mr M
Depends how far you got. Possibly 3?


Well I differentiated and then couldn't factorise so used the quadratic formula I believe...that gave me two values- pretty sure they were -3 and 44/3.
Original post by Mr M
Depends how far you got. Possibly 3?


For that question I used the quadratic formula rather than factorising but still got the answers 35/3 and 3. Would i still get all the marks? Thanks very much
Original post by GCSEsitter
For that question I used the quadratic formula rather than factorising but still got the answers 35/3 and 3. Would i still get all the marks? Thanks very much


Do you think that 71/100 will be enough for an A? Cos thats the mark I am most likely going to get? Thanks for answering.
Original post by TheEpiphany
Do you think that 71/100 will be enough for an A? Cos thats the mark I am most likely going to get? Thanks for answering.


I cant say for sure because it changes each year, but it probably will be based on peoples reactions to the test. Good luck! :smile:
Reply 57
Avatar for ab9826
ab9826
2
Original post by Mr M
How many s.f. did you use?


Four
Original post by TheEpiphany
Ah, I see my mistake. But either way when you square it for the next part of the question, doesn't the r square bit equal 20?


You square the radius not the diameter.
Original post by ab9826
Four


That's fine. You don't get penalised for being more accurate only less accurate.

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