Point in specification
What do we need to know for this point?
"use I = nqvA to explain the large range of resistivities of different materials"
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"use I = nqvA to explain the large range of resistivities of different materials"
Posted from TSR Mobile
Original post by jtbteddy
What do we need to know for this point?
"use I = nqvA to explain the large range of resistivities of different materials"
Posted from TSR Mobile
"use I = nqvA to explain the large range of resistivities of different materials"
Posted from TSR Mobile
n = density of charge carriers
q = charge of the charge carriers.
v = average speed of charge carriers.
A = area of cross-section of wire.
Dimensions = current
Density and average speed is dependent on the atomic structure of the conduction path, i.e. metal, semiconductor, shell configuration etc.
CSA affects volume of charge carriers allowed to flow.
Using ohms law V/I will determine path resistance.
Original post by uberteknik
n = density of charge carriers
q = charge of the charge carriers.
v = average speed of charge carriers.
A = area of cross-section of wire.
Dimensions = current
Density and average speed is dependent on the atomic structure of the conduction path, i.e. metal, semiconductor, shell configuration etc.
CSA affects volume of charge carriers allowed to flow.
Using ohms law V/I will determine path resistance.
q = charge of the charge carriers.
v = average speed of charge carriers.
A = area of cross-section of wire.
Dimensions = current
Density and average speed is dependent on the atomic structure of the conduction path, i.e. metal, semiconductor, shell configuration etc.
CSA affects volume of charge carriers allowed to flow.
Using ohms law V/I will determine path resistance.
Yes, but how does all this link to the resistivity?
Posted from TSR Mobile
Original post by jtbteddy
The expression gives you the current flowing through the material.
Rho = E/J
Resistivity = electric field (V.m-1/current density (A.m-2)
If you know the current flowing then resistivity is simply ohms law normalised to a unit length.
Original post by uberteknik
The expression gives you the current flowing through the material.
Rho = E/J
Resistivity = electric field (V.m-1/current density (A.m-2)
If you know the current flowing then resistivity is simply ohms law normalised to a unit length.
Rho = E/J
Resistivity = electric field (V.m-1/current density (A.m-2)
If you know the current flowing then resistivity is simply ohms law normalised to a unit length.
Thank youuuu
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