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Enzyme assay unit conversion

Hey guys

An enzyme assay is performed and the kinetic data graphed. The y-intercept of a Lineweaver-Burk plot is 0.6 min/ΔA. The substrate being assayed has a molar absorbance coefficient (ε) of 4500 L/mol.cm.

What is the V max of the enzyme in mmol/L.min?

To work this out would you not find the Vmax as 1.66ΔA/min; and then divide by the molar absorbance coefficient of 4.5 L/mmol.cm to get 0.37mmol/L.min?

I'm a bit confused.

Thanks
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So you have...Vmax which contains an absorbance value, the molar absorbance, and I assume the path length is 1cm?

A = εcl, so as you want the concentration for Vmax that will rearrange to c=A/εl

So yeah, you would be right in doing that. Sorry to explain everything that you'd already done, I thought it might help me because I haven't looked at any of my course stuff since I finished exams in May, getting a little rusty :tongue:

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