Chemistry!!HELP!!
I did this experiment
Stage 1: Accurately weigh 4.80 of copper(II) nitrate trihydrate, Cu(NO3)2.3H2O into a beaker and dissolve in 20cm3 deionised water. Slowly add 30cm3 of 2 mol dm-3 sodium hydroxide solution (NaOH), swirling your beaker continuously.
What is the balanced chemical equation?
Stage 2: Add a further 100-3 deionised water to the percipitate of copper(II) hydroxide in your beaker.
What was the purpose of adding 100-3 deionised water?
And finally, what could i do, if I was doing this reaction, to maximise the cost effectiveness of the reaction, since i found that this reaction is 63.35% in atom economy.
Stage 1: Accurately weigh 4.80 of copper(II) nitrate trihydrate, Cu(NO3)2.3H2O into a beaker and dissolve in 20cm3 deionised water. Slowly add 30cm3 of 2 mol dm-3 sodium hydroxide solution (NaOH), swirling your beaker continuously.
What is the balanced chemical equation?
Stage 2: Add a further 100-3 deionised water to the percipitate of copper(II) hydroxide in your beaker.
What was the purpose of adding 100-3 deionised water?
And finally, what could i do, if I was doing this reaction, to maximise the cost effectiveness of the reaction, since i found that this reaction is 63.35% in atom economy.
I did this experiment
Stage 1: Accurately weigh 4.80 of copper(II) nitrate trihydrate, Cu(NO3)2.3H2O into a beaker and dissolve in 20cm3 deionised water. Slowly add 30cm3 of 2 mol dm-3 sodium hydroxide solution (NaOH), swirling your beaker continuously.
What is the balanced chemical equation?
Stage 2: Add a further 100-3 deionised water to the percipitate of copper(II) hydroxide in your beaker.
What was the purpose of adding 100-3 deionised water?
And finally, what could i do, if I was doing this reaction, to maximise the cost effectiveness of the reaction, since i found that this reaction is 63.35% in atom economy.
Stage 1: Accurately weigh 4.80 of copper(II) nitrate trihydrate, Cu(NO3)2.3H2O into a beaker and dissolve in 20cm3 deionised water. Slowly add 30cm3 of 2 mol dm-3 sodium hydroxide solution (NaOH), swirling your beaker continuously.
What is the balanced chemical equation?
Stage 2: Add a further 100-3 deionised water to the percipitate of copper(II) hydroxide in your beaker.
What was the purpose of adding 100-3 deionised water?
And finally, what could i do, if I was doing this reaction, to maximise the cost effectiveness of the reaction, since i found that this reaction is 63.35% in atom economy.
Original post by Dumbledore'sArmy
I did this experiment
Stage 1: Accurately weigh 4.80 of copper(II) nitrate trihydrate, Cu(NO3)2.3H2O into a beaker and dissolve in 20cm3 deionised water. Slowly add 30cm3 of 2 mol dm-3 sodium hydroxide solution (NaOH), swirling your beaker continuously.
What is the balanced chemical equation?
Stage 2: Add a further 100-3 deionised water to the percipitate of copper(II) hydroxide in your beaker.
What was the purpose of adding 100-3 deionised water?
And finally, what could i do, if I was doing this reaction, to maximise the cost effectiveness of the reaction, since i found that this reaction is 63.35% in atom economy.
Stage 1: Accurately weigh 4.80 of copper(II) nitrate trihydrate, Cu(NO3)2.3H2O into a beaker and dissolve in 20cm3 deionised water. Slowly add 30cm3 of 2 mol dm-3 sodium hydroxide solution (NaOH), swirling your beaker continuously.
What is the balanced chemical equation?
Stage 2: Add a further 100-3 deionised water to the percipitate of copper(II) hydroxide in your beaker.
What was the purpose of adding 100-3 deionised water?
And finally, what could i do, if I was doing this reaction, to maximise the cost effectiveness of the reaction, since i found that this reaction is 63.35% in atom economy.
Heya, I'm going to put this in the chemistry forum for you as you should get more responses there.
You should also check out the forum to see if there's any other threads there which might be helpful to you!
http://www.thestudentroom.co.uk/forumdisplay.php?f=130
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