Difficult Series Question Help plz
Show that
∑r^3 + ∑r = kn(n+1) (an^2 + bn + c)
where k is a rational number and a,b,c are integers
Ive gotten to this stage:
I subbed in the appropriate formulas:
1/4n^2 (n+1)^2 + 1/2n (n+1)
Then factored out 1/2n (n+1)
1/2n (n+1) [1/2n(n+1)+1]
Expanded the square brackets:
1/2n (n+1) (1/2n^2+1/2n+1)
How do i turn a, b and c into integers?
∑r^3 + ∑r = kn(n+1) (an^2 + bn + c)
where k is a rational number and a,b,c are integers
Ive gotten to this stage:
I subbed in the appropriate formulas:
1/4n^2 (n+1)^2 + 1/2n (n+1)
Then factored out 1/2n (n+1)
1/2n (n+1) [1/2n(n+1)+1]
Expanded the square brackets:
1/2n (n+1) (1/2n^2+1/2n+1)
How do i turn a, b and c into integers?
Original post by jarjarmonkey
Show that
∑r^3 + ∑r = kn(n+1) (an^2 + bn + c)
where k is a rational number and a,b,c are integers
Ive gotten to this stage:
I subbed in the appropriate formulas:
1/4n^2 (n+1)^2 + 1/2n (n+1)
Then factored out 1/2n (n+1)
1/2n (n+1) [1/2n(n+1)+1]
Expanded the square brackets:
1/2n (n+1) (1/2n^2+1/2n+1)
How do i turn a, b and c into integers?
∑r^3 + ∑r = kn(n+1) (an^2 + bn + c)
where k is a rational number and a,b,c are integers
Ive gotten to this stage:
I subbed in the appropriate formulas:
1/4n^2 (n+1)^2 + 1/2n (n+1)
Then factored out 1/2n (n+1)
1/2n (n+1) [1/2n(n+1)+1]
Expanded the square brackets:
1/2n (n+1) (1/2n^2+1/2n+1)
How do i turn a, b and c into integers?
Factor out 1/4 instead of 1/2
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