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Integration help

How do I work out the following

∫(4−3x)−1 dx\int (4-3x)^-1\ dx?

mm I seem to get 10(4−3x)0+c\dfrac{1}{0}(4-3x)^0+c

Which doesn't seem right haha. What am I doing wrong? :redface:
Reply 1
Avatar for BabyMaths
BabyMaths
Original post by Super199
How do I work out the following

∫(4−3x)−1 dx\int (4-3x)^-1\ dx?

mm I seem to get 10(4−3x)0+c\dfrac{1}{0}(4-3x)^0+c

Which doesn't seem right haha. What am I doing wrong? :redface:


∫1udu=ln⁡u+c\int \frac{1}{u} du = \ln u + c
Reply 2
Avatar for Super199
Super199
OP
20
Original post by BabyMaths
∫1udu=ln⁡u+c\int \frac{1}{u} du = \ln u + c

mm where does this come from? Don't think we have been taught this yet
Reply 3
Avatar for Notnek
Notnek
21
Original post by Super199
mm where does this come from? Don't think we have been taught this yet

Which A Level module are you learning? And where did you get this question from?
Reply 4
Avatar for Super199
Super199
OP
20
Original post by notnek
Which A Level module are you learning? And where did you get this question from?

OCR
June 2013 paper - Thought I would have a go at a few questions. I did the first part of question 1 so thought the method of the second part would be the same. Perhaps I should attempt past paper questions after I have learnt the spec fully :tongue:
Reply 5
Avatar for davros
davros
16
Original post by Super199
OCR
June 2013 paper - Thought I would have a go at a few questions. I did the first part of question 1 so thought the method of the second part would be the same. Perhaps I should attempt past paper questions after I have learnt the spec fully :tongue:


You need to learn about the derivative of ln x, or equivalently the integral of 1/x, before you can tackle this :smile:

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