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AS Chemistry- Neutralising calculations

Hi
How would I calculate the volume of 2.50 mol dm^-3 HNO3 needed to exactly neutralise 1.50g of CaO?
Im having a blank moment and cannot for the life of me remember how to work it out! In the previous part of this question I worked out there was 0.0267 mols of CaO if thats any help?
Many thanks :smile:
If we write out the chemical equation we find that

CaO + 2 HNO3 -> Ca(NO3)2 + H2O

So for every mole of calcium oxide we require 2 moles of nitric acid. We know how many moles of calcium oxide we have, so we can work out how many moles of nitric acid we need.

Now,
Number of Moles = concentration * volume

So rearrange this to give you the volume
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Ruby1409
OP
Original post by tysonmaniac
If we write out the chemical equation we find that

CaO + 2 HNO3 -> Ca(NO3)2 + H2O

So for every mole of calcium oxide we require 2 moles of nitric acid. We know how many moles of calcium oxide we have, so we can work out how many moles of nitric acid we need.

Now,
Number of Moles = concentration * volume

So rearrange this to give you the volume


Thank for the help! :smile:
Original post by Ruby1409
Thank for the help! :smile:


Pleasure :smile:

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