Original post by Ngaden76
Someone please help solve me this question. I m stuck.
I will pm you the solution
Find the moles of HCl and NaOH
Use the ratio in the equation for the reaction between HCl and NaOH to find how many moles of acid reacted with the alkali.
Once you know the moles of acid left after the reaction with the calcium carbonate subtract this from the original number of moles in the 100 cm3 of HCl. This gives you the number of moles of HCl that reacted with the calcium carbonate. Use the ratio in the HCl + CaCO3 equation to find the moles of CaCO3 in the 1.00g of limestone and then convert this to a mass using the Mr of CaCO3. Finally calculate the % of CaCO3 in the 1.00g of limestone.
Use the ratio in the equation for the reaction between HCl and NaOH to find how many moles of acid reacted with the alkali.
Once you know the moles of acid left after the reaction with the calcium carbonate subtract this from the original number of moles in the 100 cm3 of HCl. This gives you the number of moles of HCl that reacted with the calcium carbonate. Use the ratio in the HCl + CaCO3 equation to find the moles of CaCO3 in the 1.00g of limestone and then convert this to a mass using the Mr of CaCO3. Finally calculate the % of CaCO3 in the 1.00g of limestone.
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