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Differential Equations help, please!

Hi everybody, I really need help with this question.
I know I'm supposed to rearrange the equation but I don't know how to rearrange the x part. Could anyone please help me? Thank you very much.




EDIT: Is it actually 1/y dy = 6e^3x / (2+ e^3x ) dx
Then for the RHS you change it to 2ln(2+3^3x)?
(edited 9 years ago)
Original post by Fintastic
Hi everybody, I really need help with this question.
I know I'm supposed to rearrange the equation but I don't know how to rearrange the x part. Could anyone please help me? Thank you very much.




EDIT: Is it actually 1/y dy = 6e^3x / (2+ e^3x ) dx
Then for the RHS you change it to 2ln(2+3^3x)?


Good job, your edit is the correct approach, but don't forget to plus a constant. Then you do the same to the left hand side and get a function of y in terms of x. No need to plus a constant on the left hand side since it will naturally be absorbed in the right hand side's constant anyway.

Then use the data point y = 36 and x = 0 to deduce the value of the constant.
Reply 2
Original post by Doctor_Einstein
Good job, your edit is the correct approach, but don't forget to plus a constant. Then you do the same to the left hand side and get a function of y in terms of x. No need to plus a constant on the left hand side since it will naturally be absorbed in the right hand side's constant anyway.

Then use the data point y = 36 and x = 0 to deduce the value of the constant.


Oh! Okay, thank you very much! :smile:

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