S2 Hypothesis testing question
I attach the question, my answer and the books answer. Can someone possibly help me to get the correct answer please?
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Original post by Mutleybm1996
I attach the question, my answer and the books answer. Can someone possibly help me to get the correct answer please?
Posted from TSR Mobile
I attach the question, my answer and the books answer. Can someone possibly help me to get the correct answer please?
Posted from TSR Mobile
Book's correct.
How did you arrive at your answer? Some working please.
Original post by ghostwalker
Book's correct.
How did you arrive at your answer? Some working please.
How did you arrive at your answer? Some working please.
I used p=1.5, not sure why!
I'm just a little stumped on what to do with the 1/6 as it's not in any of the tables
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Original post by Mutleybm1996
I used p=1.5, not sure why!
I'm just a little stumped on what to do with the 1/6 as it's not in any of the tables
Posted from TSR Mobile
I'm just a little stumped on what to do with the 1/6 as it's not in any of the tables
Posted from TSR Mobile
You'll have to go back to the definition of the binomial, and work out P(X=0) and P(X=1) from scratch. It's not that hard.
, with, hopefully, the obvious meanings.
(edited 9 years ago)
Original post by ghostwalker
You'll have to go back to the definition of the binomial, and work out P(X=0) and P(X=1) from scratch. It's not that hard.
, with, hopefully, the obvious meanings.
, with, hopefully, the obvious meanings.
Hi again, thank you, that worked! Could you possibly see where I've gone wrong here? I've gone wrong somewhere.
For b)P(X<3) i do p(X=0,1,2) and add them up to get 0.799
Attachment not found
Attachment not found
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(edited 9 years ago)
Original post by Mutleybm1996
Hi again, thank you, that worked!
Grand.
Could you possibly see where I've gone wrong here? I've gone wrong somewhere.
For b)P(X<3) i do p(X=0,1,2) and add them up to get 0.799
Attachment not found
Attachment not found
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I'm getting "invalid attachment" for the first two of those.
(edited 9 years ago)
Original post by ghostwalker
Grand.
I'm getting "invalid attachment" for the first two of those.
I'm getting "invalid attachment" for the first two of those.
Sorry, here
Original post by Mutleybm1996
Sorry, here
So, probability is 1- P(X=0) - P(X=1), which you had.
But P(X=0) = q^8, whereas you have 1/6 for some reason.
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