you think that (for example) 2x+4 = 2(x+2) is not a possible factorisation because there was no equation = 0?
And, please do not give "full" solutions - even when they are incorrect
I misunderstood when you said take a factor of 2 out, i thought you meant cancel the 2 out (which you would only be able to do if the equation was set to 0) so i apologize.
But i don't think my solution was incorrect.. When my factorization is multiplied out it gives the equation i started with (Obviously if it is incorrect please tell the OP how so that they don't make the same mistake)
I misunderstood when you said take a factor of 2 out, i thought you meant cancel the 2 out (which you would only be able to do if the equation was set to 0) so i apologise.
Fair enough
But i don't think my solution was incorrect.. When my factorization is multiplied out it gives the equation i started with (Obviously if it is incorrect please tell the OP how so that they don't make the same mistake)
Would you consider 4x+8 = 2(2x+4) to be the correct answer if asked to factorise - when asked to factorise there is an implied "fully"
Again, take out a factor of 2 first to make things a bit more manageable, then look at factorizing what you've got left.
What techniques do you know for factorizing quadratics when the coefficient of x^2 isn't 1?
thanks.
i've only started doing maths again after more than 6 years. i can solve equations of the form ax^2 + bx +c using 2 factors of ac which add up to make b.