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Why is x^3(7x^2+7x+6) = x(7x^2+7x+6)^3 ?

Can someone please explain this because when I sub x for any number the results are different when the exponent is in a different place. :3

Reply 1

0x2a

That isn't generally true, it's only true when x = 0 (or some other root of the polynomial you create, if it has roots that is).

EDIT: I'm assuming you mean

x^3(7x^2 + 7x + 6) = x(7x^2 + 7x + 6)^3

(edited 9 years ago)

Reply 2

TenOfThem

Original post by romama

Can someone please explain this because when I sub x for any number the results are different when the exponent is in a different place. :3

It isn't

why did you think that it was?

Reply 3

TeeEm

Original post by romama

Can someone please explain this because when I sub x for any number the results are different when the exponent is in a different place. :3

is this an equation to solve?

Reply 4

Noble.

The left hand side is a degree 5 polynomial, while the right hand side a 7...

Reply 5

davros

Original post by romama

Can someone please explain this because when I sub x for any number the results are different when the exponent is in a different place. :3

It isn't true in general if you've written it correctly!!

Reply 6

tombayes

Original post by romama

Can someone please explain this because when I sub x for any number the results are different when the exponent is in a different place. :3

there are only seven values of x for which this is true. The only real one being 0 (other 6 are complex).

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Why is x^3(7x^2+7x+6) = x(7x^2+7x+6)^3 ?

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