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Reply 1
Sorry about it being 3 hours since you posted but this is how I would do it (assuming that the third term is supposed to be 17 and not 19, otherwise there doesn't seem to be a pattern :confused:):
First you look at the 1st difference between the terms-
7,11,17,25,35

So: 4, 6, 8, 10

And then the 2nd difference-

2,2,2.

Then I would divide this by two to get 1n² or just

Next, I would take the result of away from the original terms-

7-1 = 6
11-4 = 7
17-9 = 8
25-16 = 9
35-25 = 10

So now there's a simple linear equation where the difference is 1 (so n) and then plus 5.

Overall, the nth term would be: n²+n+5

Hope this helps or it might just be rubbish if the third term actually is supposed to be 19 :smile:
Reply 2
ryanwilk
Sorry about it being 3 hours since you posted but this is how I would do it (assuming that the third term is supposed to be 17 and not 19, otherwise there doesn't seem to be a pattern :confused:):
First you look at the 1st difference between the terms-
7,11,17,25,35

So: 4, 6, 8, 10

And then the 2nd difference-

2,2,2.

Then I would divide this by two to get 1n² or just

Next, I would take the result of away from the original terms-

7-1 = 6
11-4 = 7
17-9 = 8
25-16 = 9
35-25 = 10

So now there's a simple linear equation where the difference is 1 (so n) and then plus 5.

Overall, the nth term would be: n²+n+5

Hope this helps or it might just be rubbish if the third term actually is supposed to be 19 :smile:


Thanx decent guy 4 helpin me unlike sum othas but the third term is 19 and sum how the equasion was 4n+10 or sumthing but thanks anyways :smile:
Can I suggest checking the question...
And possibly posting in the academic help forum.

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