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Differentiating Trig

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Reply 20
Original post by Peace&Love
one last question does this method just apply to problems with e in them?


y=ef(x)y = e^{f(x)}

dydx=f(x)ef(x)\frac{dy}{dx} = f'(x)e^{f(x)}

This rule only works when the function is in the form y=ef(x)y = e^{f(x)}, so yes. Only works with these kind of functions. :smile:
Original post by Zacken
y=ef(x)y = e^{f(x)}

dydx=f(x)ef(x)\frac{dy}{dx} = f'(x)e^{f(x)}

This rule only works when the function is in the form y=ef(x)y = e^{f(x)}, so yes. Only works with these kind of functions. :smile:


thank you very much, Do you have equations for problems such as xsin(^2)x, sin(^3)xcos(^3)x etc?
Reply 22
Original post by Peace&Love
one last question does this method just apply to problems with e in them?


this method works in general.

the chain rule is "DIFFERENTIATION IN LAYERS", like peeling an onion

the exponential is particularly difficult to see because of the way the function is written.

ex IS NOT a power. It is the argument of a function, like x in sin(x)


ex = EXP(x)

take my advice and speak to you teacher as I suggested earlier.
Reply 23
Original post by Peace&Love
thank you very much, Do you have equations for problems such as xsin(^2)x, sin(^3)xcos(^3)x etc?


Heard of the product rule? :smile:
Original post by Zacken
Heard of the product rule? :smile:


yeah I have done this in class & yes I will ask my teacher

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