The Student Room Group

Simultaneous equation problem

Hey, really stuck on this one
xy=56/(x-y)
x^2+y^2=113/(x-y)
Original post by Tskadem
Hey, really stuck on this one
xy=56/(x-y)
x^2+y^2=113/(x-y)


Are you sure that's 113 and not 112?
Reply 2
Nope, Diego 113


Posted from TSR Mobile
Reply 3
I think that's a typo in your textbook/whatever, it should be 112. Then you'd just do 2xy=x^2+y^2
Think about it, you get 2xy=x^2+y^2=>x^2-2xy+y^2=0=>(x-y)^2=0=>x=y.
Then plug that into the denominators and you get division by 0
derp
(edited 9 years ago)
Original post by Chlorophile
I keep getting nonsensical answers from this question too. I don't think it has any solutions.

With 113 it should have solutions, just not very nice ones, ill get some paper in a minute.
Original post by Jammy Duel
With 113 it should have solutions, just not very nice ones, ill get some paper in a minute.


I put this into an online equation solver and it actually does have very nice integer solutions. No idea how it got to them though.
Original post by Chlorophile
I put this into an online equation solver and it actually does have very nice integer solutions. No idea how it got to them though.

I think I know how to, I just can't remember it.
Looking up the solutions it seems to be obvious where they come from, so I guess work backwards.
Working forwards, not that it's necessarily helpful, I have a cubic: x^3-y^3=169.
In theory from that point you could trial and error the solutions, depending on wording of the question (if it came up in an exam) you could get away with that.
(edited 9 years ago)
Original post by Jammy Duel
Looking up the solutions it seems to be obvious where they come from, so I guess work backwards.
Working forwards, not that it's necessarily helpful, I have a cubic: x^3-y^3=169.
In theory from that point you could trial and error the solutions, depending on wording of the question (if it came up in an exam) you could get away with that.


There must be a better way of doing it though. I've come up with dozens of different forms of the equation, none of them directly lead to an obvious answer.
Original post by Chlorophile
There must be a better way of doing it though. I've come up with dozens of different forms of the equation, none of them directly lead to an obvious answer.

Well, again from knowing the solutions somewhat, there is always the spotting it from the off, which is in hindsight glaringly obvious.
Original post by Jammy Duel
Well, again from knowing the solutions somewhat, there is always the spotting it from the off, which is in hindsight glaringly obvious.


It's not that glaringly obvious. 56 appears in quite a few of the equations I came up with but so do lots of other numbers like 169, 225, 2root14, etc.
Original post by Chlorophile
It's not that glaringly obvious. 56 appears in quite a few of the equations I came up with but so do lots of other numbers like 169, 225, 2root14, etc.

Well given that it doesn't seem possible, or at least easy, to isolate either variable that it's a case of forming one of the correct set of equations, obviously trivial to solve rather than a cubic, and my line has been trying to get to that family of equations, or one of the families that would work.
Reply 15
Notice that after multiplying both equations by xyx-y the second equation can be written in terms of the first equation by manipulating the values on the RHS.

For the full solution, view the spoiler below.

Spoiler

Quick Reply

Latest