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Implicit differentiation in stats

ImageUploadedByTapatalk1416165412.605158.jpg

Hey all, would jus like to ask why does diferentiating (alpha +1) log x with respect to alpha give an answer of 1/x?? I thought the answer is logx by treating alpha as smth like x when dy/dx?
Original post by Vadevalor
ImageUploadedByTapatalk1416165412.605158.jpg

Hey all, would jus like to ask why does diferentiating (alpha +1) log x with respect to alpha give an answer of 1/x?? I thought the answer is logx by treating alpha as smth like x when dy/dx?


1/x does look wrong. Would prefer to see the whole working, rather than just that one line though.
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Vadevalor
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Original post by ghostwalker
1/x does look wrong. Would prefer to see the whole working, rather than just that one line though.


Yea i dont get it too but it was given as an answer after amendments so i thought i might have been wrong.

Here are the 2 pics, i focus on f (x l alpha) and differentiating it

ImageUploadedByTapatalk1416201853.379554.jpgImageUploadedByTapatalk1416201865.712323.jpg
Original post by Vadevalor
Yea i dont get it too but it was given as an answer after amendments so i thought i might have been wrong.

Here are the 2 pics, i focus on f (x l alpha) and differentiating it

ImageUploadedByTapatalk1416201853.379554.jpgImageUploadedByTapatalk1416201865.712323.jpg


Yep, I think it's wrong, should be "log x" at the end.

Fortunately, in the next line, we differentiate again wrt alpha and lose the term entirely.

These are meant to be partial derivatives I think, so no dy/dx, as mentioned in your first post, is required, x is treated as a constant.
(edited 9 years ago)

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