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reaction mechanism from rate equation

Hi, can anyone come up with a different mechanism? I tried but after 5 minutes gave up, i didn't spot the C=O bond, annoyingly! Grrr.

thanks
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Original post by Mutleybm1996
Hi, can anyone come up with a different mechanism? I tried but after 5 minutes gave up, i didn't spot the C=O bond, annoyingly! Grrr.

thanks


Why do you want a different mechanism? The mark scheme shows you the requirement.
Original post by charco
Why do you want a different mechanism? The mark scheme shows you the requirement.


For other interpretations. Surely there is more than one mechanism...


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twisted
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Original post by Mutleybm1996
For other interpretations. Surely there is more than one mechanism...


Posted from TSR Mobile


From what you know, no
Original post by Mutleybm1996
For other interpretations. Surely there is more than one mechanism...


Posted from TSR Mobile


The question tells you nothing about the effect of propanone on the rate (it is not investigated)

The experimental data tells you that the rate depends only on hydrogen ions not on iodine.

All you can interpret from this is that there is one hydrogen ion involved in the RDS or steps leading up to the RDS and there is no iodine.

Also the sum of the mechanistic steps must give you the stoichiometric equation.

One possibility is the answer given. Another could be:

2CH3COCH3 ---> (CH3COCH3)2 .... fast

(CH3COCH3)2 + H+ --> CH3COCH4+ + CH3COCH3 ... slow

CH3COCH4+ + I2 ---> CH3COCH2I + HI + H+ .... fast

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