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Integration by reduction question

Hi I have seen on Wikipedia that the formula for integration of x^n.(ax+b)^1/2 by reduction is given at http://en.m.wikipedia.org/wiki/Integration_by_reduction_formulae but I do not understand how they come across this. If someone could explain I would be really grateful
Reply 1
Original post by ftball22
Hi I have seen on Wikipedia that the formula for integration of x^n.(ax+b)^1/2 by reduction is given at http://en.m.wikipedia.org/wiki/Integration_by_reduction_formulae but I do not understand how they come across this. If someone could explain I would be really grateful


firstly have seen the derivation of any reduction formula, say ∫xnex dx?
Reply 2
Original post by ftball22
Hi I have seen on Wikipedia that the formula for integration of x^n.(ax+b)^1/2 by reduction is given at http://en.m.wikipedia.org/wiki/Integration_by_reduction_formulae but I do not understand how they come across this. If someone could explain I would be really grateful


In=xnax+b dxI_n=\displaystyle \int x^n\sqrt{ax+b} \ dx
If we then integrate this by parts as is normal with reduction formulae with: u=xnu=x^n, v=ax+bv=\sqrt{ax+b}
We get:

Spoiler



The step which is, I imagine, tripping you up is this one:

Spoiler



And finally, doing some simple rearranging yields the given result.

Please do try to follow through the algebra and work the details out for yourself :smile:
(edited 9 years ago)
Reply 3
Original post by joostan
In=xnax+b dxI_n=\displaystyle \int x^n\sqrt{ax+b} \ dx
If we then integrate this by parts as is normal with reduction formulae with: u=xnu=x^n, v=ax+bv=\sqrt{ax+b}
We get:

Spoiler



The step which is, I imagine, tripping you up is this one:

Spoiler



And finally, doing some simple rearranging yields the given result.

Please do try to follow through the algebra and work the details out for yourself :smile:


Hi. Thanks. Do I had actually got to the part where I alter (ax+b)^3/2 to just (ax+b). (ax+b)^1/2. Do I have to do by parts again. I can't seem to understand how you've split that up tbh
Reply 4
Original post by ftball22
Hi. Thanks. Do I had actually got to the part where I alter (ax+b)^3/2 to just (ax+b). (ax+b)^1/2. Do I have to do by parts again. I can't seem to understand how you've split that up tbh


It's simply because multiplication is distributive. . .
(ax+b)×(STUFF)=ax(STUFF)+b(STUFF)(ax+b) \times (STUFF) = ax(STUFF)+b(STUFF)

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