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Check if I got answers right

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(edited 7 years ago)
Reply 1
Avatar for Zacken
Zacken
22
Original post by iamspiderman


Can you check if I got all the answers right or wrong. Thank you!


Check your question 6 again! :smile:

Wouldn't you square each product in the bracket, that is (5a3bc4)2≡(52a6...)(5a^3bc^4)^2 \equiv (5^2a^6...) blah blah? :smile:

Also, question 8.

a−b≡1aba^{-b} \equiv \frac{1}{a^b}, so what happens to p in question 8? :smile:
(edited 9 years ago)
..
(edited 7 years ago)
Reply 3
Avatar for Zacken
Zacken
22
Original post by iamspiderman


Can you check if I got all the answers right or wrong. Thank you!


Question 14's not right either, it should come out as a natural number. Remember 321532^{\frac{1}{5}} is the fifth root of 32, that is, what number do you multiply by itself 5 times to get 32?

Hint: You calculated 2−5=1322^{-5} = \frac{1}{32}, wouldn't that mean that 25=322^5 = 32, so the fifth root of 32 is...? :smile:
(edited 9 years ago)
Original post by iamspiderman


Can you check if I got all the answers right or wrong. Thank you!


Correct except for numbers 6,8,14 and 15
Reply 5
Avatar for Zacken
Zacken
22
Original post by iamspiderman
Thanks for replying!
In question 6 wouldn't you square 5?
So the answer is: (10 a ^6 b^2 c^8)

Question 8:
1/p^3 q^2
Is that right ?


52=5×5=255^2 = 5 \times 5 = 25 :smile:

Question 8, that's correct, so you can then write that as q2p3\frac{q^2}{p^3}
Original post by iamspiderman
Thanks for replying!
In question 6 wouldn't you square 5?
So the answer is: (10 a ^6 b^2 c^8)

Question 8:
1/p^3 q^2
Is that right ?


8 is now o.k. but in 6 you have still forgotten to square the 5.

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