you've been so helpful, there is one last question that I have to do, and it looks to be a lot simpler, I just need a few things explained to me about it if you don't mind!
A sweet manufacturer found that the sales figures for a certain item depended on its selling price. The company’s market research department advised that the maximum number of items that could be sold weekly was 20000 and that the number decreased by 100 for every 1p increase in its price. The total production cost consists of a set-up cost of £200 plus 50p for every item manufactured.
If the price increase one week is p pence, find expressions in terms of p for:
(a) the number N of items sold weekly; (1 mark)
(b) the production cost £C; (2 marks)
(c) the revenue £R from the sales. (2 marks)
(d) Show that the profit £P is given by
P = 250p – 10200 – p2 (2 marks)
(e) What values of p will generate no profit? Give your answers to the nearest penny. (5 marks)
(f) From your knowledge of the behaviour of quadratic functions and using your answers to part (e), what value of p will generate the maximum profit and what is this maximum profit? (No calculus is needed.)
(4 marks)
Where it says "find expressions in terms of p", does that mean that p has to be the main focus? So p=? or just that it has to involve p?
I'm on part b. at the moment but I don't seem to be able to involve p in it. I have C=200+0.5N. Is this right so far, and any tips on how I would go about adding p into it if I need to.