The Student Room Group

Vector operators

(B dot Nabla)A

consider the above expression

Does this mean DivB in the A direction?

It appears in a vector calculus identity. Is it written in this fashion so the identity follows some logical cyclic pattern or does it mean something else?

I cannot see this meaning anything else otherwise the identity is not dimensionally correct.

Can somebody confirm please.
(edited 9 years ago)
Original post by TeeEm
(B dot Nabla)A

consider the above expression

Does this mean DivB in the A direction?

It appears in a vector calculus identity. Is it written in this fashion so the identity follows some logical cyclic pattern or does it mean something else?

I cannot see this meaning anything else otherwise the identity is not dimensionally correct.

Can somebody confirm please.


I think this might help: https://www.physicsforums.com/threads/meaning-of-a-dot-nabla-b.589069/ [post 3]

I probably can't help anymore as I am still studying vector calc myself!
Reply 2
Original post by rayquaza17
I think this might help: https://www.physicsforums.com/threads/meaning-of-a-dot-nabla-b.589069/ [post 3]

I probably can't help anymore as I am still studying vector calc myself!


definitely helps!

I will look at it in the context of my question

very messy

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