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inverse function

I have no idea for this can someone help.
consider the functionf:R^3 to R^3 defined by f (x,y,z)=(3x-y,x,z^3) a) prove it is invertable and find its inverse fiunction g
b) what are the points in R^3 where the inverse function g is differentiable
thankyou
To show it is invertible, could you show it is bijective?
Original post by omassey
I have no idea for this can someone help.
consider the functionf:R^3 to R^3 defined by f (x,y,z)=(3x-y,x,z^3) a) prove it is invertable and find its inverse fiunction g
b) what are the points in R^3 where the inverse function g is differentiable
thankyou


do you know the inverse function theorem?
Original post by tombayes
do you know the inverse function theorem?

Does that help here? The IFT is a property of *local* inverses, not global ones.

OP, I think the way to go is just to construct the inverse function directly.
Reply 4
I think i probably have to use the inverse function theorem but i dont know how too
Original post by omassey
I think i probably have to use the inverse function theorem but i dont know how too

Unless I'm being really silly, you don't need the IFT. You just need to write down the inverse and try differentiating it.
Reply 6
I dont know how to find the inverse of a function like that ive only ever done x= functions
Original post by omassey
I dont know how to find the inverse of a function like that ive only ever done x= functions

Given that f(x,y,z)=(1,0,1)f(x,y,z) = (1,0,1), can you tell me what x,y,z were?
Reply 8
Ix=0,y=-1,z=1?
Original post by omassey
Ix=0,y=-1,z=1?

Can you tell me, then, what are x,y,z if f(x,y,z)=(1,0,c)f(x,y,z) = (1,0,c)?
Reply 10
Original post by Smaug123
Can you tell me, then, what are x,y,z if f(x,y,z)=(1,0,c)f(x,y,z) = (1,0,c)?


Please help me with my mechanics question: http://www.thestudentroom.co.uk/showthread.php?t=3005989
I would appreciate it.
Original post by kcorbins
Please help me with my mechanics question: http://www.thestudentroom.co.uk/showthread.php?t=3005989
I would appreciate it.

You assume that I am any good at all at mechanics, but I'll have a look.
Reply 12
X=0,y=-1,z=cube root of three
Reply 13
Ment c
Original post by omassey
X=0,y=-1,z=cube root of three

What are x,y,z if f(x,y,z)=(1,b,c)f(x,y,z) = (1, b, c)?
Reply 15
X=b z= cube root c so im guessing y=3b-a
Original post by omassey
X=b z= cube root c so im guessing y=3b-a

Yes. So f1(a,b,c)=(b,3ba,c13)f^{-1}(a,b,c) = (b, 3b-a, c^{\frac{1}{3}}).

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