Does anyone know how to do 10-fold and 2-fold calculations for serial dilutions. Question being original stock solution of potassium permanganate was 0.05M what is the concentration of the final dilution expressed in a)molar b)millimolar and c)micromolar concentration terms
Does anyone know how to do 10-fold and 2-fold calculations for serial dilutions. Question being original stock solution of potassium permanganate was 0.05M what is the concentration of the final dilution expressed in a)molar b)millimolar and c)micromolar concentration terms
I believe this may just be an exercise in unit conversion. I may be overlooking something here but:
1a) 0.05M -> that is 0.05 Moles b) 0.05M -> x 1000 -> 50 millimolar c) 0.05M -> x 1000,000 -> 50,000 micromolar
The theory behind it, lets use a unit of measure which is more familiar in pharmacy, such as the gram. Lets say we have a 30g box of atorvastatin, but we want to find out how many kilograms and milligrams that box weighs.
30g - to get this value as kilograms, we have to divide 30g by 1000, as kilograms is a much bigger unit.
30g --> divide by 1000 --> 0.03 kg
To convert 30g into milligrams, we multiply by 1000, this is because milligrams is a much smaller unit, ie. a lot of milligrams make up a gram, because its a smaller unit of weight.
Ahh, I failed to see that you wanted to do a 2 fold and 10 fold dilution of the 0.05 M solution, BEFORE you wanted to convert it to units... Silly me. I'll try and get back to you with that one, but alas shopping awaits.