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C3 Algebra

(x^4 +x^3 +x -10)
-------------------
(x^2 +2x-3)
When setting up the remainder theorem method- why must the remainder be Dx+E?
Reply 1
Original post by MathMeister
(x^4 +x^3 +x -10)
-------------------
(x^2 +2x-3)
When setting up the remainder theorem method- why must the remainder be Dx+E?


NOT TRUE HERE

Dx2+Ex +F
Original post by TeeEm
NOT TRUE HERE

Dx2+Ex +F

My book says this... :/
F(x)=Q(x)*(divisor) + remainder
x^4+x^3+x-10= (Ax^2 +Bx+C)(X^2+2x-3)+Dx+E

Reply 3
Original post by MathMeister
My book says this... :/
F(x)=Q(x)*(divisor) + remainder
x^4+x^3+x-10= (Ax^2 +Bx+C)(X^2+2x-3)+Dx+E



yes i misread but I did not edit

I was referring to the quotient as a quadratic

that is what I meant

the remainder must be 1 degree less than the quotient, i.e. linear

Accept my apologies:colondollar:
Original post by TeeEm
yes i misread but I did not edit

the remainder must be 1 degree less than the quotient, i.e. linear
Accept my apologies:colondollar:

No problem :smile:
Why must it be 1 degree less if you don't mind?
Reply 5
Original post by MathMeister
No problem :smile:
Why must it be 1 degree less if you don't mind?


otherwise it will "go" once more if you carry out a long division.

it is equivalent to the fact that if you divide by 7 for example your remainder has to be 6 or less
Original post by TeeEm
otherwise it will "go" once more if you carry out a long division.

it is equivalent to the fact that if you divide by 7 for example your remainder has to be 6 or less

That's what I thought- I just needed certainty- thanks! :biggrin:
Reply 7
Original post by MathMeister
That's what I thought- I just needed certainty- thanks! :biggrin:


no problems

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