How to work out this equation?

I did a combustion of fuels experiment in class.
The work requires me to
Use the mass from the spirit burner and its calorific value to work out the energy supplied.

The energy stored in the water can be worked out using (see image)

What do I do? Please help me
Its so confusing

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No idea why Δθ and not ΔT, no wonder you feel confused.

Physics uses $\Delta \theta$, I think that's where they got it from.

Where are you getting that from? T is used universally for temperature. θ is normally used for angles

Where are you getting that from? T is used universally for temperature. θ is normally used for angles

It's not delta theta, it's just theta. It's used for temperature change.

Where are you getting that from? T is used universally for temperature. θ is normally used for angles

It is $\Delta \theta$ delta theta as defined in physics and removes ambiguity in simply using T.

The equation is a statement of the heat energy lost or gained by a mass of given specific heat when subject to a change in temperature.

E = heat energy gained or lost

m = mass

C = specific heat

$\theta$ = temperature ($\theta$ reserved for Centigrade, T reserved for Kelvin)

$\Delta$ = change in the immediately following variable ($\theta$ in this instance or $T$ in others)

therefore: $\Delta \theta = (\theta_{initial} - \theta_{final})$ with temperature stated in degrees centigrade.

It is $\Delta \theta$ delta theta as defined in physics and removes ambiguity in simply using T.

The equation is a statement of the heat energy lost or gained by a mass of given specific heat when subject to a change in temperature.

E = heat energy gained or lost

m = mass

C = specific heat

$\theta$ = temperature ($\theta$ reserved for Centigrade, T reserved for Kelvin)

$\Delta$ = change in the immediately following variable ($\theta$ in this instance or $T$ in others)

therefore: $\Delta \theta = (\theta_{initial} - \theta_{final})$ with temperature stated in degrees centigrade.

I agree that the strict physics definition uses theta for temperature in Celsius but in common school use it denotes temperature change.

http://www.bbc.co.uk/schools/gcsebitesize/science/aqa/heatingandcooling/buildingsrev3.shtml
... and 1 million other references which give the equation as E=mc

Yeah, bbc bite size GCSE is such a reliable source of scientific data don't you think...

Not true. $\theta$ is used for temperature as well as angles, polar co-ordinates and the eighth star in astronomical constellations.

The angles in polar co-ordinates are no different from any other angles.