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As level physics forces help

Can some help me with this problem
the answer is something like 357.23
dont understand why?????
you need to look at the up and down components and also the left and right components. use trig to split up the 300 N force into an up and a right component.
Reply 2
Original post by Imrankhan0121
Can some help me with this problem
the answer is something like 357.23
dont understand why?????



Do you know how to add vectors?
Original post by lerjj
Do you know how to add vectors?


Yep I do
I tried to resolve the upward force by 1000-500 =500 downwards
Then add the wind horizontal force by doing this cos45*300=212.13
Original post by the bear
you need to look at the up and down components and also the left and right components. use trig to split up the 300 N force into an up and a right component.

Yep I do
I tried to resolve the upward force by 1000-500 =500 downwards
Then add the wind horizontal force by doing this cos45*300=212.13

Show me the solution
the 300N also has an upwards component.
Reply 6
Original post by Imrankhan0121
Yep I do
I tried to resolve the upward force by 1000-500 =500 downwards
Then add the wind horizontal force by doing this cos45*300=212.13

Show me the solution


The wind has components of force in both the horizontal and vertical direction. So find the resultant in both directions, and use Pythagoras.
(edited 9 years ago)
Original post by the bear
the 300N also has an upwards component.


Ok 212 +500=712

1000-712=287
Original post by Phichi
The wind has components of force in both the horizontal and vertical direction. So find the resultant in both directions, and use Pythagoras.


Ok 212 +500=712

1000-712=287
Reply 9
Original post by Imrankhan0121
Ok 212 +500=712

1000-712=287


I don't think you've grasped what I said. Firstly, the 212N force from the wind in the horizontal direction acts upwards, however the resultant between the 1000N and 500N force on the parachute is 500N downwards, meaning that the resultant in the vertical direction is 500-212 downwards. Secondly, you need to calculate the force of the wind in the horizontal direction, using sine, fortunately it's also 212N though, as the triangle is 45 degrees. Add these two using pythagoras, draw a triangle with 500-212 down and 212 right, and you'll see the resultant is the hypotenuse.
Original post by Phichi
I don't think you've grasped what I said. Firstly, the 212N force from the wind in the horizontal direction acts upwards, however the resultant between the 1000N and 500N force on the parachute is 500N downwards, meaning that the resultant in the vertical direction is 500-212 downwards. Secondly, you need to calculate the force of the wind in the horizontal direction, using sine, fortunately it's also 212N though, as the triangle is 45 degrees. Add these two using pythagoras, draw a triangle with 500-212 down and 212 right, and you'll see the resultant is the hypotenuse.


288squated +212squared(because of horizontal )= 194
Reply 11
Original post by Imrankhan0121
288squated +212squared(because of horizontal )= 194


If you root what you have just written, I don't get 194.
Original post by Phichi
If you root what you have just written, I don't get 194.


Ok thanks my calculator was mess
Vector resolving can be tricky... I've made a couple of videos that may be helpful in understanding the solution to this problem:

[video="youtube;_Avje8lzC5c"]https://www.youtube.com/watch?v=_Avje8lzC5c[/video]

If you find these helpful, see the links in my signature for more videos that I've made for my students.
Original post by mrcowentweets
Vector resolving can be tricky... I've made a couple of videos that may be helpful in understanding the solution to this problem:

[video="youtube;_Avje8lzC5c"]https://www.youtube.com/watch?v=_Avje8lzC5c[/video]

If you find these helpful, see the links in my signature for more videos that I've made for my students.


Your vids are useful
Can u click my profile because I have made a thread called forces help ASAP and answer the question
Please

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