Impedance circuit
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For part b of this question is this the correct circuit diagram?
If not can someone point me towards the correct setup as for me the wording of the question isnt clear...
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Original post by Goods
For part b of this question is this the correct circuit diagram?
If not can someone point me towards the correct setup as for me the wording of the question isnt clear...
Posted from TSR Mobile
Attachment not found
For part b of this question is this the correct circuit diagram?
If not can someone point me towards the correct setup as for me the wording of the question isnt clear...
Posted from TSR Mobile
Your file attachment is not loading. Can you repost please? Ta.
Original post by uberteknik
Hi.
Your file attachment is not loading. Can you repost please? Ta.
Your file attachment is not loading. Can you repost please? Ta.
Posted from TSR Mobile
Original post by Goods
No worries.
C3 represents the lumped cable capacitance which the question says Is between the input to the oscilloscope and ground.
Therefore C3 should be parallel with the oscilloscope input impedance.
(Values in the attached diagram are not quite the same as your question).
(edited 9 years ago)
Original post by uberteknik
so removing the text is this the circuit in question? where v2 is the voltage across only the right hand RC parallel section?
Original post by Goods
so removing the text is this the circuit in question? where v2 is the voltage across only the right hand RC parallel section?
You got it!
Original post by Goods
so removing the text is this the circuit in question? where v2 is the voltage across only the right hand RC parallel section?
The connecting cable is co-axial: a single test-signal conductor sheathed in a braided shield (Faraday cage) connected to ground.
The shield is isolated from the signal conductor by a rigid pvc spacer which has an air core (dielectric) to aid mechanical flexibility.
In other words, the connecting cable forms a capacitor whose total capacitance is a function of the dielectric properties, cable length and spacing.
(edited 9 years ago)
Original post by uberteknik
You got it!
I followed that arrangement and arrived at this, but from here I have no idea how to work out c1 such that v2/v1 is independent of w. Ive checked a few times and get the same fraction for v2/v1....
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