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Check answer

(edited 7 years ago)

The question is :
An electronic component allows a current of 10mA to flow through it when a voltage of 2V is applied. When voltage is increased to 8V, the current which flows is 60mA. Does the component obey ohms law?

I said no it doesn't, as my working out got me 30mA, instead of 60mA. I did:

Resistance : r= v/I
2v / 10mA = 0.2ohm

Current: I= delta V/ R

6/ 0.2 = 30mA

Not sure...

Not "delta V"
You just apply Ohm's Law again with V=8Volts

It's true though that the component doesn't obey Ohm's Law, but your reasoning isn't correct.

The best way to do this is look at the ratio of V/ I in both cases.
It should be the same if Ohm's Law is obeyed.
It clearly isn't here.

2/0.010
and
8/ 0.060