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rate of reaction

hi guys,
i was wondering why the order of [A] and are 1 and 2 respectively?
FullSizeRender.jpg
thanks
Reply 1
Avatar for Pigster
Pigster
20
Comparing 1&2, doubling B quadruples rate, 2nd order WRT B.
Comparing 2&3, doubling B (again) should make rate x4, BUT it is x8, i.e. something has made rate x2 bigger than expected! Since A has doubled, it must be 1st order WRT A.
Reply 2
Avatar for 041087
041087
OP
2
Original post by Pigster
Comparing 1&2, doubling B quadruples rate, 2nd order WRT B.
Comparing 2&3, doubling B (again) should make rate x4, BUT it is x8, i.e. something has made rate x2 bigger than expected! Since A has doubled, it must be 1st order WRT A.


Why A is first order? I still don't really understand:redface:
Reply 3
Avatar for Pigster
Pigster
20
Comparing 2&3, has doubled and since we know it is 2nd order WRT rate should be 4x what is was in expt. 2, i.e. 12.06 (12.1 3s.f.). BUT rate is 24.1 in expt. 3, i.e. 2x higher than it should be! What is making expt. 3 go 2x faster than expected? Perhaps it has something to do with the fact that [A] is 2x bigger? Since [A] = 2x and rate is also 2x, it must be 1st order WRT [A].
Original post by 041087
Why A is first order? I still don't really understand:redface:

Do you understand what the order of a reaction means?

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