Solubility Question
Any thoughts on Bii and Biii, I calculated Bi to be 1.67x10-8
I figured common-ion effect for bii, as theres more Cu2+ions.
So the equil equation becomes Ksp = 3[Cu]3 x [CuSO4]. Solving for [Cu] gives 3.73x10-13
Cheers
I figured common-ion effect for bii, as theres more Cu2+ions.
So the equil equation becomes Ksp = 3[Cu]3 x [CuSO4]. Solving for [Cu] gives 3.73x10-13
Cheers
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