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Standard Deviation

Just to be sure, is this the correct method of finding standard deviation from ungrouped data:



Thanks.
Reply 1
Original post by Abdul-Karim
Just to be sure, is this the correct method of finding standard deviation from ungrouped data:



Thanks.


I know nothing about spread sheets but by trying to read waht is going on I am assuming you are trying to find the standard deviation of 12 numbers

I got a different answer...
Original post by TeeEm
I know nothing about spread sheets but by trying to read waht is going on I am assuming you are trying to find the standard deviation of 12 numbers

I got a different answer...


Correct, could you point me in the right direction.

From my understanding, I found the variance = (SumOf(frequency-mean)^2)/SumOfFrequency

I don't know the keyboard codes for them ^ and then the standard deviation is simply the square root of that??

Btw I've rounded the mean to the nearest integer, for simplification purposes.
Reply 3
Original post by Abdul-Karim
Correct, could you point me in the right direction.

From my understanding, I found the variance = (SumOf(frequency-mean)^2)/SumOfFrequency

I don't know the keyboard codes for them ^ and then the standard deviation is simply the square root of that??

Btw I've rounded the mean to the nearest integer, for simplification purposes.


i only see 12 numbers ...

what is the sum of frequency?
Original post by TeeEm
i only see 12 numbers ...

what is the sum of frequency?


I would assume it's the sum of all the test scores, is it not?

Or am I meant to divide by the sum of observations? which would be 12.
Reply 5
Original post by Abdul-Karim
I would assume it's the sum of all the test scores, is it not?

Or am I meant to divide by the sum of observations? which would be 12.


I have no idea what the question is ...

I am trying to decipher it by looking to the spreadsheet.

If I am assuming the right things the variance is 2621/12
i checked using an online calculator ?

datawork.jpg
Original post by the bear
i checked using an online calculator ?



Yeah I got it, thanks.

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