Can anyone help me?
The equation is x^3+y^3=3xy
It is said that find the stationary values and determine whether they are maxima or minima.
I differentiate it fist and get dy/dx=(y-x^2)/(y^2-x)
and then get dy/dx=0 and y-x^2=0. So y=x^2
I have already find out the stationary points (0,0) and (cube root of 2, cube root of 4) .
(cube root of 2, cube root of 4 )is a maximum point if I substitute is into the second derivative.
However, At point (0,0) the second derivative of the function =0 then how do I know whether it is a maxima or minima?
Thanks a lot!!