The Student Room Group
Uni students - Complete our survey >>
Uni students - Complete our survey >>
Uni students - Complete our survey >>

Help on a maths question

Scroll to see replies

Original post by physicsmaths
Yes but u couldve just done -2x-3/4=3/2 so a^3/2 but yh thats aroota.


Posted from TSR Mobile


Cool, so what is the final answer of the whole question?
2 root 2, a root a?
Original post by Chittesh14
Cool, so what is the final answer of the whole question?
2 root 2, a root a?


Yep i think so.


Posted from TSR Mobile
Original post by physicsmaths
Yep i think so.


Posted from TSR Mobile


Thanks, so my brother was correct! He was just partly confused as i misguided him lol. He got 2 root 2, a root a aswell. Also, I will ask him this too and I want to ask you aswell if you don't mind, why does the a have to be calculated seperately. Why can't we just do 1/1/4a^-2 = 4a^2 and then work out from there (4a^2)^3/4.

Why do you have to work them out both seperately?
Original post by Chittesh14
Thanks, so my brother was correct! He was just partly confused as i misguided him lol. He got 2 root 2, a root a aswell. Also, I will ask him this too and I want to ask you aswell if you don't mind, why does the a have to be calculated seperately. Why can't we just do 1/1/4a^-2 = 4a^2 and then work out from there (4a^2)^3/4.

Why do you have to work them out both seperately?


Well each has to be calculated but I only separated the number out to demonstrate the invalidity of your 16
Original post by TenOfThem
Well each has to be calculated but I only separated the number out to demonstrate the invalidity of your 16


Oh right. So usually you should seperate out the number and the term to work out the real answer, or you could be misunderstood and come up with a different answer.
Original post by Chittesh14
Thanks, so my brother was correct! He was just partly confused as i misguided him lol. He got 2 root 2, a root a aswell. Also, I will ask him this too and I want to ask you aswell if you don't mind, why does the a have to be calculated seperately. Why can't we just do 1/1/4a^-2 = 4a^2 and then work out from there (4a^2)^3/4.

Why do you have to work them out both seperately?


You dont. You can just do it together.


Posted from TSR Mobile
Original post by physicsmaths
You dont. You can just do it together.


Posted from TSR Mobile


I don't understand, if you do it all together, how will it work out. That is basically doing 1/4(1/a^2) = 1/4a^2.
If you then do (1/4a^2)^-3/4 it becomes 1/1/4a^2 = 1/4a^2
(1/4a^2)^3/4 = fourth root of (1/4a^2) = root a / root 2
if u cube it then a root a / 2 root 2 or other way round. wow ur excellent dude thanks :biggrin:.
(edited 9 years ago)
legend.png2.8KB
legend 2.png1.9KB
Original post by Chittesh14
I don't understand, if you do it all together, how will it work out. That is basically doing 1/4(1/a^2) = 1/4a^2.
If you then do (1/4a^2)^-3/4 it becomes 1/1/4a^2 = 1/4a^2
(1/4a^2)^3/4 = fourth root of (1/4a^2) = root a / root 2
if u cube it then a root a / 2 root 2 or other way round. wow ur excellent dude thanks :biggrin:.


Have you done C1?


Posted from TSR Mobile
Original post by physicsmaths
Have you done C1?


Posted from TSR Mobile


Nope, I'm gcse, year 10.


Posted from TSR Mobile

Quick Reply

Related discussions

Latest

Trending

Trending

Articles for you