calculating equilibrium concentrations
Im a little stuck on this other question, not sure how to handle it..
NH2COONH4 (s) (equilibrium signs) 2NH3 (g) + CO2 (g)
2 moles of NH2COONH4 form at equilibrium, 2 moles of NH3 form at equilibrium...its asking how much
NH2COONH4 formed initially and how much CO2 formed at eq.
Problem for me here is, the reactant is in a solid state, so it shouldnt be included and its equilibirum conc not worked out right? but then the reaction wouldnt occur...but the question is asking me to find these conc. values.
Im stumped on what to do
NH2COONH4 (s) (equilibrium signs) 2NH3 (g) + CO2 (g)
2 moles of NH2COONH4 form at equilibrium, 2 moles of NH3 form at equilibrium...its asking how much
NH2COONH4 formed initially and how much CO2 formed at eq.
Problem for me here is, the reactant is in a solid state, so it shouldnt be included and its equilibirum conc not worked out right? but then the reaction wouldnt occur...but the question is asking me to find these conc. values.
Im stumped on what to do
from what you write the answer is only looking for the number of moles, not the concentration. You are right, the solid would not appear in the equilibrium expression and would not be involved in calculating Kc.
NH2COONH4 <--> 2NH3 + CO2
initial moles ? 0 0
eqm moles 2 2 ?
assuming 1 mole of NH2COONH4 splits into 2 moles of NH3 and 1 mole of CO2 from the balanced symbol equation, if 2 moles of NH3 exist at eqm, 1 mole of NH2COONH4 must have split to form that. if there are still 2 moles of NH2COONH4 left at eqm there must have been 3 moles initially. And if 2 moles of NH3 have been formed at eqm, 1 mole of CO2 would be formed as its a 2 : 1 ratio
so initial moles of NH2COONH4 = 3
eqm moles of CO2 = 1
thats going on the question as you wrote it anyways!
NH2COONH4 <--> 2NH3 + CO2
initial moles ? 0 0
eqm moles 2 2 ?
assuming 1 mole of NH2COONH4 splits into 2 moles of NH3 and 1 mole of CO2 from the balanced symbol equation, if 2 moles of NH3 exist at eqm, 1 mole of NH2COONH4 must have split to form that. if there are still 2 moles of NH2COONH4 left at eqm there must have been 3 moles initially. And if 2 moles of NH3 have been formed at eqm, 1 mole of CO2 would be formed as its a 2 : 1 ratio
so initial moles of NH2COONH4 = 3
eqm moles of CO2 = 1
thats going on the question as you wrote it anyways!
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