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Where did i go wrong :( easy mechanics



I feel so stupid missing the first Q but i swear it seems correct
Reply 1
Bump
Original post by naxiv
Bump


You seem to be applying the sine rule. That will relate the lengths of the sides of the triangle formed by the strings but says nothing about the tensions in them.

You need to apply Newton 2 horizontally, by resolving the two forces into vertical/horizontal components.
Reply 3
Doesnt the sine rule so apply for forcrs
Original post by atsruser
You seem to be applying the sine rule. That will relate the lengths of the sides of the triangle formed by the strings but says nothing about the tensions in them.

You need to apply Newton 2 horizontally, by resolving the two forces into vertical/horizontal components.
Original post by naxiv
Doesnt the sine rule so apply for forcrs


It can apply to forces, if you are using it in a vector diagram whose lengths represent the magnitudes of the forces, but here, you have a picture of a couple of strings; they are not forces themselves, although they produce the force. The lengths of the strings says nothing about the tension in the strings. For example, a 1 kg mass hanging stationary on the end of a 1 m rope produces the same tension as a 1 kg mass on the end of a 10 m rope.
Yeah, you're over complicating it :smile: just resolve left and right
(edited 9 years ago)

Original post by naxiv
Doesnt the sine rule so apply for forcrs



Not when there's a weight on one of the corners

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