Integration of brackets
y=x(x-3)^2
Not sure if I expanded the brackets first, then apply the coeffecient or if the coeffecient is applied first; then the results integrated.
Not sure if I expanded the brackets first, then apply the coeffecient or if the coeffecient is applied first; then the results integrated.
Original post by apronedsamurai
y=x(x-3)^2
Not sure if I expanded the brackets first, then apply the coeffecient or if the coeffecient is applied first; then the results integrated.
Not sure if I expanded the brackets first, then apply the coeffecient or if the coeffecient is applied first; then the results integrated.
Assuming you're doing basic integration, you need to expand the brackets first.
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